PSI math

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I agree.


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PSI outside the system is 0 / atmospheric. Psi only affects the velocity of the water which is part of the equation for energy. There is usually a factor determined empirically which relates the drag force on the 'object' in question to its velocity and in air its usually a square or higher order so it will slow down very quickly, and there's got to be a lot of other stuff unique to the spray into air situation. So in summary effective psi is not the right question, whatever the right measure is it drops off very quickly - one inch, cut your hand off - three inches, exfoliating - 12 inches, wash your dog.
 
Don't forget the effect that heat has on PSI. The hotter you go, the more PSI you wil have in the coil, where the pressure and temperature are measured. Once it leaves the tip of the gun, or the pressure vessel, the PSI will drop a ton.
 
I guess I'm asking the impact question, but at further distances than the surface cleaner we were talking about before.

Try this question instead:

5 gpm @ 3500 psi at the tip @ 12 inches from the surface = x impact



a)5 gpm @ 2000 psi at the tip @ ?? inches from the surface = x impact (x being the same as (a) above)

b)5 gpm @ 1500 psi at the tip @ ?? inches from the surface = x impact (x being the same as (a) above)

c) 5 gpm @ 1000 psi at the tip @ ?? inches from the surface = x impact (x being the same as (a) above)

d) 5 gpm @ 700 psi at the tip @ ?? inches from the surface = x impact (x being the same as (a) above)

Fill in the ?? on a,b,c and d and that is the answers I'm looking for.
 
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