Maximum Entropy?

Nigel, what does the equation under your avatar stand for? I forget what the K is for.
 
Scott Stone said:
As soon as the water exits the tip of the wand, it will be affected, because it will no longer be in the pressure vessel. In this case, the hose and coil is the pressure vessel. Try this, turn on the heater on your pressure washer. Have someone hold the gun, and put your hand in the flow of the water at the furthest point. At that point, how much pressure are you feeling, and how much heat are you feeling? Gradually move your hand towards the tip of the wand. Notice when you start feeling the heat from the gun. There is a very real possibility that you will not be able to feel the heat go up significantly until you can barely stand to hold your hand in the pressure.

This is part of the reason why I find it so amusing when I watch someone clean something without a surface cleaner, holding the wand 2 feet from something, thinking that the pressure is helping to clean whatever it is.
Click to expand...


Because most of us use expanding nozzles to clean. The greater the nozzle angle for the same distance away from the nozzle the temperature is lower.

This is one of the reasons why I think Jim, of Crystal Cleaning Company had such success in concrete cleaning, in addition to his top secret soap, he used zero degree nozzles at temps will above boiling.

Expansion is virtually nil for a greater distance from the zero nozzle, so the temperature he produced actually impacted the surface. Not to mention he would have the highest impact of any angled nozzle and his pump could produce 4350 psi.
 
So force = .0526*flow*PSI

or .0526*5.5GPM* 3500 PSI = 1012.55
or .0526*8*3000=1262.4
or .0526*500GPM*60PSI =1578
 
Scott Stone said:
So force = .0526*flow*PSI

or .0526*5.5GPM* 3500 PSI = 1012.55
or .0526*8*3000=1262.4
or .0526*500GPM*60PSI =1578
Click to expand...


Not quite, you forgot the square root

Theoretical Impact = K x Flow (gpm) X square root of psi

I dont use the numerical value for "k" because I am comparing it to other values that have "k" in it so the bigger number in front of "k" has the higher theoretical impact.

For a 5.5 machine @ 3500 psi = 5.5 x 3500^(1/2) = 5.5 multiply by the square root of pressure.

so for common "General" pumps in the pressure wash industry:

T1511 (1450 rpm)= K x 4 x 3500^(1/2) = 236.64 K

TS2021 (1450 rpm)= K x 5.6 x 3500^(1/2) = 331.3 K

TSF2021 (1450 rpm)= K x 7.0 x 3600^(1/2) = 420 K

TSF2021 (1750 rpm) = K x 8.5 x 3600^(1/2) = 510 K

TSF2221 (1450 rpm)= K x 8.5 X 3000^(1/2) = 465.56 K

TSF2221 (1750rpm) = K x 10.2 x 3000^(1/2) = 558.68 K

now look at General pumps high pressure commercial pumps "TSP series"

TSP1619 (1450 rpm) = K x 3.6 x 7250^(1/2) = 306.53 K
TSP1619 (1750 rpm) = K x 4.3 x 5800^(1/2) = 327.47 K

See the TSP's have more psi but the impact is greater on a TS2021, however this only holds true for nozzles used other than zero degree.

Impact with a zero degree is 1.9 x psi

So if you took a TS2021 5.6 gpm @ 3500 psi used you red nozzle,

Impact would be 1.9 x pressure = 1.9 x 3500 = 6650

Now a TSP1619 (1450rpm) with red nozzle = 1.9 X 7250 = 13775

High flow and moderate pressure for general cleaning, higher pressuse for sewer jetting and blasting, especially when a zero tip is used
 
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