Paul Kassander
New member
I can help with Udor if you like, Sent you a PM.
The spec sheet says it will do the following:
1. 12 gpm @ 2500 psi spinning at 1750 rpm
2. 10 gpm @ 3000 psi spinning at 1450rpm
If the following is correct, can I sping the pump at a lower rpm to produce approximately 8 gpm. If I figure correctly for every 145 or 150 rpm gets 1 gallon of water.... so If I spin it at @1200 rpm, will it do 8 gpm at 3000 psi?
Also, what is the mathematical formula for figuring out the pulley ratios. If I had a 3.75 inch pulley on the engine and wanted 1200 pump rpm, what size pulley would I need?
Thanks for the help is anyone knows......I was never a great math student.
Mike.